Matemáticas

Preguntas

(×-5)(×-3)(×₊1)(×₊3)-(ײ-2×-9)²₊36


1 Respuesta

  • [tex] \left(x-5\right)\left(x-3\right)\left(x+1\right)\left(x+3\right)-\left(x^2-2x-9\right)^2+36=0 [/tex]

    [tex] \left(x^2-2x-9\right)^2=\left(x^2-2x-9\right)\left(x^2-2x-9\right) [/tex]

    [tex] =\left(x-5\right)\left(x-3\right)\left(x+1\right)\left(x+3\right)-\left(x^2-2x-9\right)\left(x^2-2x-9\right)+36 [/tex]

    [tex] \left(x^3-7x^2+7x+15\right)\left(x+3\right):\quad x^4-4x^3-14x^2+36x+45 [/tex]

    [tex] -\left(x^2-2x-9\right)\left(x^2-2x-9\right):\quad -x^4+4x^3+14x^2-36x-81 [/tex]

    [tex] x^4-4x^3-14x^2+36x+45-x^4+4x^3+14x^2-36x-81+36:\quad [/tex]

    x=0